Anna University Plus Career & Placement Zone Interview Prep Top 25 Aptitude Questions for Freshers (with Detailed Solutions)

Top 25 Aptitude Questions for Freshers (with Detailed Solutions)

Top 25 Aptitude Questions for Freshers (with Detailed Solutions)

 
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08-15-2025, 04:36 AM
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Top 25 Aptitude Questions for Freshers (with Detailed Solutions)

Aptitude tests are a common part of campus placements, competitive exams, and fresher job interviews. They measure your problem-solving ability, logical reasoning, and numerical skills. 

In this guide, we’ve compiled the Top 25 Aptitude Questions for Freshers along with step-by-step solutions so you can practice and prepare with confidence.

Tip: Time yourself while solving to improve speed and accuracy.


1. A train 180 meters long is running at 54 km/hr. In how much time will it pass a man standing on the platform? 
Solution: 
Speed = 54 km/hr = (54 × 1000) / 3600 = 15 m/s 
Time = Distance / Speed = 180 / 15 = 12 seconds


2. The average of five numbers is 27. If one number is excluded, the average becomes 25. Find the excluded number. 
Solution: 
Sum of 5 numbers = 27 × 5 = 135 
Sum of remaining 4 numbers = 25 × 4 = 100 
Excluded number = 135 – 100 = 35


3. A man sells an article for ₹900 at a profit of 20%. Find the cost price. 
Solution: 
SP = CP + 20% of CP = 1.2 × CP 
CP = 900 / 1.2 = ₹750


4. If 3 workers complete a job in 6 days, how many workers are needed to complete the same job in 2 days? 
Solution: 
Work = Workers × Days 
3 × 6 = x × 2 → x = 9 workers 
Answer: 9 workers


5. A sum of ₹5000 is lent at simple interest at 10% per annum. Find the interest after 3 years. 
Solution: 
SI = (P × R × T) / 100 = (5000 × 10 × 3) / 100 = ₹1500


6. The LCM of two numbers is 60, and their HCF is 5. If one number is 15, find the other. 
Solution: 
Product of numbers = LCM × HCF = 60 × 5 = 300 
Other number = 300 / 15 = 20


7. A man covers a certain distance at 60 km/hr and returns at 40 km/hr. Find the average speed. 
Solution: 
Average speed = (2 × 60 × 40) / (60 + 40) = 4800 / 100 = 48 km/hr


8. If 15 men can do a work in 20 days, how long will 25 men take to finish the same work? 
Solution: 
Men × Days = Constant 
15 × 20 = 25 × x → x = (300 / 25) = 12 days


9. A person bought a pen for ₹120 and sold it for ₹150. Find the profit percentage. 
Solution: 
Profit = 150 – 120 = ₹30 
Profit% = (30 / 120) × 100 = 25%


10. The perimeter of a rectangle is 50 m. If the length is 15 m, find the breadth. 
Solution: 
Perimeter = 2(L + B) → 50 = 2(15 + B) → 15 + B = 25 → B = 10 m


11. The sum of two numbers is 50, and their difference is 10. Find the numbers. 
Solution: 
Let numbers = x, y 
x + y = 50, x – y = 10 
Adding: 2x = 60 → x = 30 
y = 20 
Answer: 30 and 20


12. A car travels 90 km in 2 hours and 30 minutes. Find its speed in km/hr. 
Solution: 
Time = 2.5 hrs 
Speed = Distance / Time = 90 / 2.5 = 36 km/hr


13. Find the simple interest on ₹8000 at 5% for 4 years. 
Solution: 
SI = (8000 × 5 × 4) / 100 = ₹1600


14. The selling price of an article is ₹480 and the profit is 20%. Find the cost price. 
Solution: 
SP = 1.2 × CP → CP = 480 / 1.2 = ₹400


15. A man rows 10 km downstream in 2 hours and 6 km upstream in 2 hours. Find the speed of the boat in still water and the speed of the current. 
Solution: 
Downstream speed = 10 / 2 = 5 km/hr 
Upstream speed = 6 / 2 = 3 km/hr 
Boat speed = (5 + 3) / 2 = 4 km/hr 
Current speed = (5 – 3) / 2 = 1 km/hr


16. Find the value of x: 3x + 5 = 20 
Solution: 
3x = 15 → x = 5


17. A sum amounts to ₹660 in 2 years at simple interest. If the principal is ₹600, find the rate of interest. 
Solution: 
SI = 660 – 600 = ₹60 
Rate = (SI × 100) / (P × T) = (60 × 100) / (600 × 2) = 5%


18. The average of 8 numbers is 14. If one number is 20, find the average of the remaining 7 numbers. 
Solution: 
Sum of 8 numbers = 14 × 8 = 112 
Sum of remaining 7 = 112 – 20 = 92 
Average = 92 / 7 = 13.14


19. If a man walks at 4 km/hr, he is late by 15 minutes. If he walks at 5 km/hr, he reaches on time. Find the distance. 
Solution: 
Let distance = d km 
d/4 – d/5 = 15/60 = 1/4 
(5d – 4d) / 20 = 1/4 → d = 5 km


20. The ratio of ages of A and B is 3:4. After 6 years, their ages will be 21 and 28. Find their present ages. 
Solution: 
Present age of A = 21 – 6 = 15 
Present age of B = 28 – 6 = 22 
Answer: 15 and 22


21. A person buys 4 pens for ₹40 and sells them at ₹15 each. Find the profit percentage. 
Solution: 
CP = ₹40, SP = ₹60, Profit = ₹20 
Profit% = (20 / 40) × 100 = 50%


22. The cost of 12 mangoes is ₹144. What will be the cost of 8 mangoes? 
Solution: 
Cost per mango = 144 / 12 = ₹12 
Cost of 8 = 8 × 12 = ₹96


23. The sum of two numbers is 70 and their product is 1296. Find the numbers. 
Solution: 
Let numbers be x and y 
x + y = 70, xy = 1296 
Equation: t² – 70t + 1296 = 0 
Factors: (t – 54)(t – 16) = 0 
Answer: 54 and 16


24. The difference between simple interest and compound interest on ₹5000 at 10% for 2 years is? 
Solution: 
SI = (5000 × 10 × 2) / 100 = ₹1000 
CI = 5000 × (1.1)² – 5000 = ₹1050 
Difference = 1050 – 1000 = ₹50


25. A man spends 60% of his income and saves ₹2400. Find his income. 
Solution: 
Savings% = 40% → 40% = ₹2400 
100% = (2400 × 100) / 40 = ₹6000


Conclusion 
Practicing aptitude questions regularly will help you build speed and accuracy for placement tests, competitive exams, and job interviews. Bookmark this page and revisit it often for revision.

Keywords: Aptitude Questions for Freshers, Aptitude Test Preparation, Placement Aptitude Questions, Interview Aptitude Problems with Answers
Admin
08-15-2025, 04:36 AM #1

Top 25 Aptitude Questions for Freshers (with Detailed Solutions)

Aptitude tests are a common part of campus placements, competitive exams, and fresher job interviews. They measure your problem-solving ability, logical reasoning, and numerical skills. 

In this guide, we’ve compiled the Top 25 Aptitude Questions for Freshers along with step-by-step solutions so you can practice and prepare with confidence.

Tip: Time yourself while solving to improve speed and accuracy.


1. A train 180 meters long is running at 54 km/hr. In how much time will it pass a man standing on the platform? 
Solution: 
Speed = 54 km/hr = (54 × 1000) / 3600 = 15 m/s 
Time = Distance / Speed = 180 / 15 = 12 seconds


2. The average of five numbers is 27. If one number is excluded, the average becomes 25. Find the excluded number. 
Solution: 
Sum of 5 numbers = 27 × 5 = 135 
Sum of remaining 4 numbers = 25 × 4 = 100 
Excluded number = 135 – 100 = 35


3. A man sells an article for ₹900 at a profit of 20%. Find the cost price. 
Solution: 
SP = CP + 20% of CP = 1.2 × CP 
CP = 900 / 1.2 = ₹750


4. If 3 workers complete a job in 6 days, how many workers are needed to complete the same job in 2 days? 
Solution: 
Work = Workers × Days 
3 × 6 = x × 2 → x = 9 workers 
Answer: 9 workers


5. A sum of ₹5000 is lent at simple interest at 10% per annum. Find the interest after 3 years. 
Solution: 
SI = (P × R × T) / 100 = (5000 × 10 × 3) / 100 = ₹1500


6. The LCM of two numbers is 60, and their HCF is 5. If one number is 15, find the other. 
Solution: 
Product of numbers = LCM × HCF = 60 × 5 = 300 
Other number = 300 / 15 = 20


7. A man covers a certain distance at 60 km/hr and returns at 40 km/hr. Find the average speed. 
Solution: 
Average speed = (2 × 60 × 40) / (60 + 40) = 4800 / 100 = 48 km/hr


8. If 15 men can do a work in 20 days, how long will 25 men take to finish the same work? 
Solution: 
Men × Days = Constant 
15 × 20 = 25 × x → x = (300 / 25) = 12 days


9. A person bought a pen for ₹120 and sold it for ₹150. Find the profit percentage. 
Solution: 
Profit = 150 – 120 = ₹30 
Profit% = (30 / 120) × 100 = 25%


10. The perimeter of a rectangle is 50 m. If the length is 15 m, find the breadth. 
Solution: 
Perimeter = 2(L + B) → 50 = 2(15 + B) → 15 + B = 25 → B = 10 m


11. The sum of two numbers is 50, and their difference is 10. Find the numbers. 
Solution: 
Let numbers = x, y 
x + y = 50, x – y = 10 
Adding: 2x = 60 → x = 30 
y = 20 
Answer: 30 and 20


12. A car travels 90 km in 2 hours and 30 minutes. Find its speed in km/hr. 
Solution: 
Time = 2.5 hrs 
Speed = Distance / Time = 90 / 2.5 = 36 km/hr


13. Find the simple interest on ₹8000 at 5% for 4 years. 
Solution: 
SI = (8000 × 5 × 4) / 100 = ₹1600


14. The selling price of an article is ₹480 and the profit is 20%. Find the cost price. 
Solution: 
SP = 1.2 × CP → CP = 480 / 1.2 = ₹400


15. A man rows 10 km downstream in 2 hours and 6 km upstream in 2 hours. Find the speed of the boat in still water and the speed of the current. 
Solution: 
Downstream speed = 10 / 2 = 5 km/hr 
Upstream speed = 6 / 2 = 3 km/hr 
Boat speed = (5 + 3) / 2 = 4 km/hr 
Current speed = (5 – 3) / 2 = 1 km/hr


16. Find the value of x: 3x + 5 = 20 
Solution: 
3x = 15 → x = 5


17. A sum amounts to ₹660 in 2 years at simple interest. If the principal is ₹600, find the rate of interest. 
Solution: 
SI = 660 – 600 = ₹60 
Rate = (SI × 100) / (P × T) = (60 × 100) / (600 × 2) = 5%


18. The average of 8 numbers is 14. If one number is 20, find the average of the remaining 7 numbers. 
Solution: 
Sum of 8 numbers = 14 × 8 = 112 
Sum of remaining 7 = 112 – 20 = 92 
Average = 92 / 7 = 13.14


19. If a man walks at 4 km/hr, he is late by 15 minutes. If he walks at 5 km/hr, he reaches on time. Find the distance. 
Solution: 
Let distance = d km 
d/4 – d/5 = 15/60 = 1/4 
(5d – 4d) / 20 = 1/4 → d = 5 km


20. The ratio of ages of A and B is 3:4. After 6 years, their ages will be 21 and 28. Find their present ages. 
Solution: 
Present age of A = 21 – 6 = 15 
Present age of B = 28 – 6 = 22 
Answer: 15 and 22


21. A person buys 4 pens for ₹40 and sells them at ₹15 each. Find the profit percentage. 
Solution: 
CP = ₹40, SP = ₹60, Profit = ₹20 
Profit% = (20 / 40) × 100 = 50%


22. The cost of 12 mangoes is ₹144. What will be the cost of 8 mangoes? 
Solution: 
Cost per mango = 144 / 12 = ₹12 
Cost of 8 = 8 × 12 = ₹96


23. The sum of two numbers is 70 and their product is 1296. Find the numbers. 
Solution: 
Let numbers be x and y 
x + y = 70, xy = 1296 
Equation: t² – 70t + 1296 = 0 
Factors: (t – 54)(t – 16) = 0 
Answer: 54 and 16


24. The difference between simple interest and compound interest on ₹5000 at 10% for 2 years is? 
Solution: 
SI = (5000 × 10 × 2) / 100 = ₹1000 
CI = 5000 × (1.1)² – 5000 = ₹1050 
Difference = 1050 – 1000 = ₹50


25. A man spends 60% of his income and saves ₹2400. Find his income. 
Solution: 
Savings% = 40% → 40% = ₹2400 
100% = (2400 × 100) / 40 = ₹6000


Conclusion 
Practicing aptitude questions regularly will help you build speed and accuracy for placement tests, competitive exams, and job interviews. Bookmark this page and revisit it often for revision.

Keywords: Aptitude Questions for Freshers, Aptitude Test Preparation, Placement Aptitude Questions, Interview Aptitude Problems with Answers

 
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